Natu and Buchku each have a certain number of | vedclass

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(B) Let the number of oranges with Natu be $N$ and the number of oranges with Buchku be $B$.According to the first statement: $N + 10 = 2(B - 10)$.Sim

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$70, 50$

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(B) Let the number of oranges with Natu be $N$ and the number of oranges with Buchku be $B$.According to the first statement: $N + 10 = 2(B - 10)$.Simplifying this: $N + 10 = 2B - 20$,which gives $2B - N = 30$ (Equation $1$).According to the second statement: $B + 10 = N - 10$.Simplifying this: $N - B = 20$ (Equation $2$).From Equation $2$,we get $N = B + 20$.Substituting this into Equation $1$: $2B - (B + 20) = 30$.$2B - B - 20 = 30$,so $B = 50$.Now,$N = 50 + 20 = 70$.Thus,Natu has $70$ oranges and Buchku has $50$ oranges.

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